fprintf row indentation export
7 views (last 30 days)
Show older comments
I'm having trouble correctly exporting a custom text file I need. When I use fprintf within a for loop, I am getting strange formatting issues with spacing occuring before the beginning of every 5th row starting with row 6.
fileout = 'q.txt';
fid2 = fopen( fileout, 'w' );
for row = 1:5:n;
fprintf( fid2, ' %s %s %s %s\r\n', rough_cell{ row, : } );
fprintf( fid2, ' %s %s %s %s\r\n', rough_cell{ row+1, : } );
fprintf( fid2, ' %s %s %s %s\r\n', rough_cell{ row+2, : } );
fprintf( fid2, ' %s %s %s %s\r\n', rough_cell{ row+3, : } );
fprintf( fid2, ' %s %s %s\r\n', rough_cell{ row+4, : } );
end
fclose( fid2 );
Here is a sample of what the output text file looks like. Every 5th row aside from the 1st row is indented by about 8 spaces. I cannot figure out why my code is doing this. If I eliminate the last, shorter fprintf line within the for loop, I don't have this problem. However, I need to have every fifth row in output as well as the remaining alternating first four rows. As can be seen, there is no additional spacing in the formatSpec (just 1 space). I've also checked the rough_cell cell array and there is no additional spacing for the first column of every fifth row.
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02
-9.9900000E+02 -9.9900000E+02 -9.9900000E+02 -9.9900000E+02
Any ideas?
6 Comments
dpb
on 9 Sep 2013
num2str( rough.blk, '%9.7E')
I didn't dig thru it all entirely, but it's possible the ill-formed format string could possibly contribute to the problem.
An E format w/ a precision of 7 digits needs a minimum of 14 spaces for the field accounting for the sign place, a leading digit, the decimal and the four for the exponent. Not sure what C (hence Matlab) does when there isn't enough room...
Walter Roberson
on 9 Sep 2013
The 9 would be the minimum width, and more width will be silently used if needed to satisfy the precision and format specifier.
Accepted Answer
Walter Roberson
on 8 Sep 2013
Change
fid2 = fopen( fileout, 'w' );
to
fid2 = fopen( fileout, 'wt' );
and remove the \r from each of the format strings.
Note: how it shows up will depend on which method you use to output it. Not all MS Windows operations know that \r\n is to be treated together as a single newline.
7 Comments
More Answers (0)
See Also
Categories
Find more on Characters and Strings in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!