How to limit operation range of bsxfun(@plus,a,b)

Hi all, I would like to use bsxfun to add an element (from range 1) ONLY to the array resulting in the 2nd range of i. The code below results in addition of dp(5) to the hole array (i=1:1:10) what I dont want. Any proposals!? Thanks in advance!

for i=1:1:5
x(i)=i;
[dp(i)] = myfunction(x(i))
end

for i=6:1:10
x(i)=i;
[dp(i)] = myfunction(x(i))
dp_out=bsxfun(@plus,dp,dp(5))  
end

end

[Jan]

You can omit the square brackets around the output of myFunction.

I do not understand the question. What mean "from range 1"? And what is the 2nd range of i? Could you give us a small example?

[Horst Guenter]

With "from range 1" I mean the output of myfunction for i=0:1:5. And "2nd range of i" is meant the output of myfunction for i=6:1:10. The crrent output is as below:

dp=[2 1 1 1 1 3 3 3 3 3]

I would like to get the following result:

dp=[2 1 1 1 1 5 5 5 5 5]

Thanks!

[the cyclist]

I am a little confused now, but I am 99% certain that you do not need bsxfun, and can use something simple like the answer I have entered below.

Answer 1

[the cyclist]

Is dp a vector, or some other shape?

Can you simply do

>> dp(5:10) = dp(5:10) + dp(5)

?