steepest descent using secant method

2 views (last 30 days)
Hacer Busra KELES
Hacer Busra KELES on 4 May 2021
Commented: SALAH ALRABEEI on 21 Jun 2021
I am trying the sovee function the steepest descent algrot using secant method but ı guess my code is wrong how can fixed;
syms X1 x2;
f = x1.^4/8 + x2.^2/4 -2*x1-4*x1*x2;
x1(1) = 2;
x2(1) = 2;
df_dx1 = diff(f, X);
df_dx2 = diff(f, Y);
g0 = [subs(df_dx1,[X,Y], [x1(1),x2(1)]) subs(df_dx2, [X1,X2], [x1(1),x2(1)])];
d = -(g0);
for i = 1:5
I = [x1(i),x1(i)];
syms t
g = subs(f, [X,Y], [x1(i)+d(1)*t,x2(i)+t*d(2)]);
dg_dt = diff(g,t);
t = solve(dg_dt, t);
x1(i+1) = I(1)+t*d(1);
x2(i+1) = I(2)+t*d(2);
g_o = [subs(df_dx,[X,Y], [x1(i),y(i)]) subs(df_dy, [X1,X2], [x(i),x2(i)])];
i = i+1;
g_1 = [subs(df_dx1,[X1,X2], [x1(i),X2(i)]) subs(df_dx2, [X1,X2], [x1(i),x2(i)])];
d=-(g_1);
end
Iter = 1:i;
X_coordinate = x1';
Y_coordinate = x2';
Iterations = Iter';
T = table(Iterations,X_coordinate,Y_coordinate);
fcontour(f, 'Fill', 'On');
hold on;
plot(x1,x2,'*-r');
fprintf('Initial Objective Function Value: %d\n\n',subs(f,[X1,X2], [x1(1),x2(1)]));
fprintf('Number of Iterations for Convergence: %d\n\n', i);
fprintf('Point of Minima: [%d,%d]\n\n', x1(i), x2(i));
fprintf('Objective Function Minimum Value after Optimization: %d\n\n', subs(f,[X1,X2], [x1(i),x2(i)]));
disp(T)
  2 Comments
SALAH ALRABEEI
SALAH ALRABEEI on 21 Jun 2021
your function depends on X1 and X2 variables, while you differentiated wrt X and Y, HOW COME!
SALAH ALRABEEI
SALAH ALRABEEI on 21 Jun 2021
You have to double chceck your code first, your function has X1 and X2 variables, so whenever you use diff or subs, you have to keep them. here you have also y and x2 as both number of variable.

Sign in to comment.

Answers (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!