Don't know what is wrong with this double integral code
3 views (last 30 days)
Show older comments
I'm trying to write a script that can calculate the double integral of a function. What I want to do is this:
- move along the y-axis.
- for each value of y, I calculate the area of the cross-section of the 3D graph, which is the integral of the function for x at that specific value of y.
- I multiply this area by a small increment in y to get an elemental volume.
- I add up all these volumes up to get the final volume under the graph, which is equal to the double integral.
I don't know why my code isn't giving me the write answer for sin(x)*sin(y) between 0 and pi for x limits and 0 and pi for y limits.
I attach my code as a .m file and also below:
f = @(a, b) sin(a)*sin(b);
x0 = 0;
xn = pi; % Integral limits
n = 1000*pi; % No. intervals for x
y0 = 0;
ym = pi; % Integral limits
m = 1000*pi; % No. intervals for y
hx = (xn - x0)/n; % x step size
hy = (ym - y0)/m; % y step size
I = 0;
for y = y0:hy:ym
A = 0;
for x = x0:hx:xn
A = A + hx*f(x,y);
A = A - 0.5*hx*(f(x0,y) + f(xn,y));
I = I + A*hy;
end
end
0 Comments
Answers (1)
Bjorn Gustavsson
on 3 Feb 2021
Use integral2 instead. That should solve this type of problem.
HTH
0 Comments
See Also
Categories
Find more on Numerical Integration and Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!