How to solve integration of squared root function

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i want to solve
∫(x/(x-(dp/dr)))dr where p is function of r
  3 Comments
Jui Sen
Jui Sen on 6 Sep 2020
Hi, thank you for your response.
P(r) is a value between 0 & 1 . In other words, p(r) ∈ [0,1] & it depends on the value of r
x is a constant value. Its not a function of r.
Walter Roberson
Walter Roberson on 6 Sep 2020
Is p( r) a known function?
Is there a reason to not use
integral(@(r) x./(x-p(r)), LowerBound, UpperBound)

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