Reshape array by moving row below to end of column above

Hello all,

I have run into a unique reshaping problem and would greatly appreciate any help.

Say I have an array:

A= (1:63)';

Within "A" there are "n" chunks of data that need to be sorted. In this example, there are 3 chunks of data each with 21 values.

n = 3;

I need to reshape "A" into a horizontal row vector "B" with the following pattern:

B = [1 22 43 2 23 44 3 24 45 .....]

I am working on a very large optimization problem so I am trying to avoid any loops if possible.

I greatly appreciate any possible solutions or if someone can point me in the right direction,

-Chris H.

[Christopher]

Walter,

Thank you very much for your prompt and concise answer, it was exactly what I was looking for!

-Chris H.

Answer 1

[Walter Roberson]

reshape(reshape(A, [], n).', 1,[])