Table shows [1x1 sym]

Hello all,

I'm a beginner on MatLab, as you can see looking at my code. :/

I made a table results, but some columns show [1x1 sym] instead of the numeric value.

>> T

T =

  10×8 table

      x       r_radius        a         a_prime       beta        beta_i         psi       c_radius 
    ______    ________    _________    _________    _________    _________    _________    _________

         1    0.13333     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    1.7222    0.22963     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    2.4444    0.32593     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    3.1667    0.42222     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    3.8889    0.51852     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    4.6111    0.61481     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    5.3333    0.71111     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    6.0556    0.80741     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
    6.7778     0.9037     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]
       7.5          1     [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]    [1x1 sym]

When I check in the Command Window the matrices that don't show up in the table, it does return the numeric values.

a =
 
 0.31698729810778067661813841462353
  0.3262837777440087165440265301808
 0.32954671600852516464237599910151
  0.3309989121113711334050402800197
 0.33175810683123203783836260106585
 0.33220147460088597174212384813428
 0.33248184041064921067847020995443
 0.33267000685409559982051967533792
 0.33280224969353673811924615373881
 0.33289865996267927658115250868875

Although, there is a bunch of decimals, I thought it may be the source of the problem.

So I tried to use the round function, with 3 decimals for instead, but it shows the error:

>> round(a,3)
Error using sym/round
Too many input arguments.

I had found those values with the vpasolve function, which seems to give me a result full of decimals, maybe that's the source of the problem (Also, as a beginner, my code is very clinky and I have difficulties to resolve this system of equation at once, but I made it work...).

Would you have an idea to solve this please ? :)

%a
syms a1 a2 a3 a4 a5 a6 a7 a8 a9 a10
x=linspace(1,TSR,10)';
eqn1=(x(1)==(4*a1-1)*sqrt((1-a1)/(1-3*a1)));
eqn2=(x(2)==(4*a2-1)*sqrt((1-a2)/(1-3*a2)));
eqn3=(x(3)==(4*a3-1)*sqrt((1-a3)/(1-3*a3)));
eqn4=(x(4)==(4*a4-1)*sqrt((1-a4)/(1-3*a4)));
eqn5=(x(5)==(4*a5-1)*sqrt((1-a5)/(1-3*a5)));
eqn6=(x(6)==(4*a6-1)*sqrt((1-a6)/(1-3*a6)));
eqn7=(x(7)==(4*a7-1)*sqrt((1-a7)/(1-3*a7)));
eqn8=(x(8)==(4*a8-1)*sqrt((1-a8)/(1-3*a8)));
eqn9=(x(9)==(4*a9-1)*sqrt((1-a9)/(1-3*a9)));
eqn10=(x(10)==(4*a10-1)*sqrt((1-a10)/(1-3*a10)));
a1=vpasolve(eqn1,a1,[1/4 1/3]); %Finding a between 1/4 and 1/3
a2=vpasolve(eqn2,a2,[1/4 1/3]);
a3=vpasolve(eqn3,a3,[1/4 1/3]);
a4=vpasolve(eqn4,a4,[1/4 1/3]);
a5=vpasolve(eqn5,a5,[1/4 1/3]);
a6=vpasolve(eqn6,a6,[1/4 1/3]);
a7=vpasolve(eqn7,a7,[1/4 1/3]);
a8=vpasolve(eqn8,a8,[1/4 1/3]);
a9=vpasolve(eqn9,a9,[1/4 1/3]);
a10=vpasolve(eqn10,a10,[1/4 1/3]);
a=[a1;a2;a3;a4;a5;a6;a7;a8;a9;a10];

Answer 1

[Alex Mcaulley]

You need to convert the symbolic values to double for all the cases:

a1=double(vpasolve(eqn1,a1,[1/4 1/3]));

[Bertrand Canetti]

That's it! Thanks Alex! :)

[Peter Perkins]

Just to try to shed some light on what's going on: tables can contain almost any type of MATLAB variable, but not all variables display in a form that's compatible with the tabular form needed by a table's display. So table just shows the type and size, and because it needs to show one value per row of the table, it displays each row of the sym as [1x1 sym] when in fact, in the table, the sym is stored as an Nx1 vector.

In this case, the table display could do better and display the values, because that sym is in fact "tabular".