How to generate a vector of character values?

I want to generate a vector A with all character values 1, 2, 3...N; For example, A=['1','2','3'...], N is changeable and can be defined beforehand. How can I do that?

Answer 1

[Guillaume]

Your question is not very clear. Note that character '1' has a value of 49. Also note that there are only 10 characters which represents numerical digits, the characters '0123456789'. Finally also note that A=['1','2','3','4'] is exactly the same as A='1234'. If you want separate char arrays, each a textual representation of number you need to put the array in a cell array, A={'1','2','3','4'}, or a string array, A=["1","2","3","4"].

So, if you wanted to generate all characters with values between 1 and N, you'd use

char(1:N)

Be aware that characters with value below 32 are non-printable characters.

If you wanted to generate the digit characters starting at '1' up to maximum of 9, then

char((1:N) + '0')

Of course, if N is greater than 9, this will generate non-digit characters since as stated there's only 10 of them (and '0' is before '1')

If you wanted to generate a cell array of char array, each the numeric representation of an integer from 1 to N (with N potentially greater than 9):

compose('%d', 1:N)  %for a cell array of char arrays
compose("%d", 1:N)  %for a string array

Did I mention that the question was not clear?

[JING JIAO]

compose("%d", 1:N) %for a string array works for me

Answer 2

[Steven Lord]

Does it have to be a char vector, or is a string vector acceptable?

N = 42;
S = string(1:N)