calculate the magnitude of matrix

i want to calculate the magnitude of each row, for example row 1 contains the following values (0,20,10), the magnitude of this row is 22.36067977. i want to do the same for the entire list. please help. t=[0:0.4:40]'; s0=zeros(size(t)); b=[s0,s0,10-(t/4).^2]; a=[20*sin(t),20*cos(t),s0]; s0=a+b

s0 =

         0   20.0000   10.0000
    7.7884   18.4212    9.9900
   14.3471   13.9341    9.9600
   18.6408    7.2472    9.9100
   19.9915   -0.5840    9.8400
   18.1859   -8.3229    9.7500
   13.5093  -14.7479    9.6400
    6.6998  -18.8444    9.5100
   -1.1675  -19.9659    9.3600
   -8.8504  -17.9352    9.1900
  -15.1360  -13.0729    9.0000
  -19.0320   -6.1467    8.7900
  -19.9233    1.7500    8.5600
  -17.6691    9.3703    8.3100
  -12.6253   15.5113    8.0400
   -5.5883   19.2034    7.7500
    2.3310   19.8637    7.4400
    9.8823   17.3879    7.1100
   15.8734   12.1670    6.7600
   19.3584    5.0252    6.3900
   19.7872   -2.9100    6.0000
   17.0920  -10.3858    5.5900
   11.6983  -16.2219    5.1600
    4.4578  -19.4969    4.7100
   -3.4865  -19.6938    4.2400
  -10.8804  -16.7814    3.7500
  -16.5565  -11.2197    3.2400
  -19.6187   -3.8866    2.7100
  -19.5836    4.0601    2.1600
  -16.4566   11.3658    1.5900
  -10.7315   16.8771    1.0000
   -3.3121   19.7238    0.3900
    4.6302   19.4567   -0.2400
   11.8415   16.1177   -0.8900
   17.1832   10.2341   -1.5600
   19.8121    2.7347   -2.2500
   19.3132   -5.1963   -2.9600
   15.7650  -12.3070   -3.6900
    9.7280  -17.4747   -4.4400
    2.1551  -19.8836   -5.2100
   -5.7581  -19.1532   -6.0000
  -12.7621  -15.3990   -6.8100
  -17.7513   -9.2136   -7.6400
  -19.9380   -1.5736   -8.4900
  -18.9769    6.3149   -9.3600
  -15.0197   13.2063  -10.2500
   -8.6913   18.0128  -11.1600
   -0.9907   19.9754  -12.0900
    6.8663   18.7844  -13.0400
   13.6393   14.6277  -14.0100
   18.2589    8.1616  -15.0000
   19.9959    0.4070  -16.0100
   18.5759   -7.4119  -17.0400
   14.2232  -14.0606  -18.0900
    7.6250  -18.4894  -19.1600
   -0.1770  -19.9992  -20.2500
   -7.9511  -18.3516  -21.3600
  -14.4699  -13.8066  -22.4900
  -18.7042   -7.0819  -23.6400
  -19.9855    0.7609  -24.8100
  -18.1116    8.4836  -26.0000
  -13.3782   14.8669  -27.2100
   -6.5327   18.9030  -28.4400
    1.3442   19.9548  -29.6900
    9.0088   17.8561  -30.9600
   15.2512   12.9384  -32.2500
   19.0857    5.9780  -33.5600
   19.9070   -1.9263  -34.8900
   17.5855   -9.5264  -36.2400
   12.4875  -15.6225  -37.6100
    5.4181  -19.2521  -39.0000
   -2.5067  -19.8423  -40.4100
  -10.0358  -17.2998  -41.8400
  -15.9804  -12.0260  -43.2900
  -19.4021   -4.8537  -44.7600
  -19.7606    3.0850  -46.2500
  -16.9994   10.5367  -47.7600
  -11.5543   16.3248  -49.2900
   -4.2851   19.5356  -50.8400
    3.6607   19.6621  -52.4100
   11.0285   16.6845  -54.0000
   16.6552   11.0727  -55.6100
   19.6524    3.7128  -57.2400
   19.5469   -4.2333  -58.8900
   16.3553  -11.5110  -60.5600
   10.5817  -16.9714  -62.2500
    3.1374  -19.7524  -63.9600
   -4.8022  -19.4149  -65.6900
  -11.9837  -16.0122  -67.4400
  -17.2731  -10.0816  -69.2100
  -19.8356   -2.5593  -71.0000
  -19.2664    5.3671  -72.8100
  -15.6555   12.4461  -74.6400
   -9.5729   17.5602  -76.4900
   -1.9790   19.9018  -78.3600
    5.9274   19.1015  -80.2500
   12.8979   15.2854  -82.1600
   17.8322    9.0561  -84.0900
   19.9511    1.3970  -86.0400
   18.9203   -6.4826  -88.0100
   14.9023  -13.3388  -90.0000

Answer 1

[Birdman]

s0_square=s0.^2;
sqrt(sum(s0_square(1:size(s0_square),:)'))'

Answer 2

[Steven Lord]

If you're using release R2017b or later, use vecnorm. You'll need to specify both the norm p and the dimension dim to calculate the norm of the rows.