Im trying to find the absolute value of the difference between current value 'c' and the values 'n'.

Im trying to find the absolute value of the difference between current value 'c' and the values 'n'. Matlab keeps coming back saying 'Subscripted assignment dimension mismatch.'

E=[363725;142414;795692;184315];

c=E(3,1);

n = [4;9;8]

for i=1:length(n)

   N(1,i) = abs(c-n(1,i));
end

What is wrong with the second line in my for loop?

Answer 1

[Image Analyst]

You say n(1,i), meaning the 3rd column of the first row. However, n is a column vector with only one column, not 3. Don't use 1, or ,1 when dealing with row or column vectors - it's not needed and just complicates things.

The fix:

E=[363725;142414;795692;184315]
c=E(3)
n = [4;9;8]
for i=1:length(n)
   N(i) = abs(c-n(i))
end

Answer 2

[James Tursa]

Change n(1,i) to n(i). n is a column vector but you are indexing into it as if it were a row vector. You could use n(i,1), but n(i) is simpler for vector indexing. You might want to change the N indexing as well.

[Paris Mayberry]

thanks, although i changed that it still didnt work. this loop is within a function and an input to the function is c=[3,1], i think it isnt working because c needs to be changed from the position to the actual element with in this case is 7(from the array E) but im not sure of how to do this?