The complex number integration

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lick liao
lick liao on 13 Sep 2017
Commented: Star Strider on 14 Sep 2017
I have some complex number integration to solve.
Here is my equation: z=exp^(j*2*pi*f) H=(abs(2*z^(-1)-z^(-2)))^2
I want to calculate the integtion of H from f=0 to f=a
I use the int(), but it only return the function I write. It seems it can't calculate out the answer.
Is someone who know how to deal with the problem? Thank for your reply!

Accepted Answer

Star Strider
Star Strider on 13 Sep 2017
I would eliminate the abs call until the end, using it on the integrated function only after you evaluate it numerically.
Try this:
syms a f real
z(f) = exp(1j*2*pi*f);
H(f) = (2/z - 1/z^2)^2;
H = rewrite(H, 'sincos'); % Optional, If You Want a Trigonometric Result
IH = int(H, f, 0, a);
IH = simplify(IH, 'Steps', 20)
  2 Comments
lick liao
lick liao on 14 Sep 2017
Edited: lick liao on 14 Sep 2017
Thanks a lot.
You give me another way to think about the equation.
I transfer H(z) to trigonometric form, then get the final answer.
Star Strider
Star Strider on 14 Sep 2017
As always, my pleasure.

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