how to solve this error horzcat Dimensions of matrices being concatenated are not consistent?

hi all, how can i solve this error:

Error using horzcat
Dimensions of matrices being concatenated are not consistent

in this code?

Error in Gauss (line 9)
Aug=[A b];

or this code:

    function x=Gauss(A,b)
    A=[0 4 2;10 -2 -7;-7 2 3];
    b=[-24 10 15];
    [m,n]=size(A);
    if m~=n
        error('A matriz deve ser quadrada');
    end
    nb=n+1;
    Aug=[A b];
    for k=1:n-1
        for i=k+1:n
            factor=Aug(i,k)/Aug(k,k);
            Aug(i,k:nb)=Aug(i,k:nb)-factor*Aug(k,k:nb);
        end
    end
    x=zeros(n,1);
    x(n)=Aug(n,nb)/Aug(n,n);
    for i=n-1:-1:1
        x(i)=(Aug(i,nb)-Aug(i,i+1:n)*x(i+1:n))/Aug(i,i);
    end
    x(i);

ps. i am new in matlab.

Cheers!

Answer 1

[Walter Roberson]

Your A is 3 x 3. You are trying to add on additional columns that are 1 x 3. You are asking that a matrix like this be constructed:

   0  4  2  -24  10  5
  10 -2 -7    X   X  X
  -7  2  3    X   X  X

where the X represents a "hole", a non-existent location.

Matrices in MATLAB must be rectangular.

Hint:

   b.'

[victor caixeta]

Got it! Thanks!

[Kristen Jones]

So, what did you do to solve your problem? Do you put an X?

[Walter Roberson]

Aug=[A b];

was the existing code. The solution was to use

Aug=[A b.'];

Answer 2

[Ratam Mahi]

Error using horzcat
Dimensions of matrices being concatenated are not consistent.

Error in Module1_Training (line 17)
    db=[F c];

[Walter Roberson]

What is size(F) and size(c) ?

In order to concatenate you need ndims(F) == ndims(c) and size(F,1) == size(c,1)