How do I set the value of the heaviside function at the origin (or shifted origin) to be 1, not 0.5?

I'm running Matlab R2014a, and I'd like to utilise the heaviside function to activate different parts of an equation at different points in time.

At a time t', a term becomes valid, so I'd like the full magnitude of that. By using heaviside as is, I get 0.5 times that term for the first array value, then the full magnitude there after. i.e. heaviside(t-t').*y, where y is a function to be acitvated at t=t'. I get 0.5*y(t'), when I would like 1*y(t').

After checking online, it seems the 'sympref' function is not on this version of matlab, so does anyone know the correct method?

[jgg]

Could you try something like handling the case where t-t' differently? Maybe this guy could help there> I was thinking like

 g(t') = max(heaviside(t-t'),kroneckerDelta(t-t'))*y(t')

would probably work, although it's not that elegant.

[Oliver]

Well, I ended up doing the following, which isn't elegant, but works.

 theta2 = heaviside(t-t')';
 theta2(t') = theta2(t')*2;

[jgg]

I'd suggest answering your own question with this, so people know how to solve the problem.

[Jovana Nojic]

You can use: round(heaviside(t-t'))

Answer 1

[Oliver]

This works fine, but there's probably a more elegant way to do it...

theta2 = heaviside(t-t')';
theta2(t') = theta2(t')*2;

[Jos (10584)]

t' is not a valid variable name ... the symbol ' is the conjugate transpose operator.

Answer 2

[Stephen23]

This is equivalent to

myHeav = @(X)double(X>=0);

Answer 3

[Jos (10584)]

theta2 = ceil(heaviside(t-t_origin))

which is the same as Stephens solution,

theta2 = double(t >= t_origin)

which is also much faster ...