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Finding small vector in big vector

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Hey everybody,
I am desperately looking for a function that can find a small vector inside a big vector. Ismember and interesect just wouldn't do it right :(
Let's say I have the two vectors x = [ 7 6 9 7 4 3 7 9 0 7 4 3 2 6 7 0 7 5 ]; y = [ 4 3 2 6 ]
As a result I would like to have ans = [ 11 12 13 14 ]
so only the coordinates of where the values are in the correct sequence. Is there anything that can do that?
Thanks in advance!

Accepted Answer

Image Analyst
Image Analyst on 20 Oct 2015
Try this:
x = [ 7 6 9 7 4 3 7 9 0 7 4 3 2 6 7 0 7 5 ];
y = [ 4 3 2 6 ];
% As a result I would like to have ans = [ 11 12 13 14 ]
out = strfind(x, y) + [0:length(y)-1]
  2 Comments
Lennart
Lennart on 21 Oct 2015
Edited: Image Analyst on 21 Oct 2015
Wohoo awesome. Thank you guys so much! That just works perfectly. Actually the strfind itself is just what I need, but the idea of "+[0 : length(y)-1] " is quite needed as well.
Image Analyst
Image Analyst on 21 Oct 2015
You're welcome. strfind(x, y) finds only 11 - the start of the sequence - while adding that other vector gives you [11,12,13,14] which is what you said you wanted.

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More Answers (2)

James Tursa
James Tursa on 20 Oct 2015
Edited: James Tursa on 20 Oct 2015
I am not on a machine with MATLAB at the moment to test this, but maybe try the strfind(x,y) function to see if it works with doubles (even though the doc doesn't indicate that it does).
  3 Comments
Bruno Luong
Bruno Luong on 12 Sep 2022
Edited: Bruno Luong on 12 May 2024
@Alexander Paul "The numbers are internally casted to char."
I don't think so, if it was, the result of the two last commands would be indentiical
d = double('a')+0.1;
a = 'a';
strfind(d,a)
ans = []
strfind(char(d),char(a))
ans = 1
Alexander
Alexander on 12 Sep 2022
You are right. I checked it only with uint8.

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Matlab Pro
Matlab Pro on 12 May 2024
Hi
A small improvement where the sub-vector is found more than once...
x = x(:)'; % Make sure data is a Row vector
ix = strfind(x, y);
if length(ix)>1 % Fix cases where y is found more than once
idx = [1:length(y)] + ix(1)-1; % Indexes of 1st occurance
else
idx = strfind(x, y) + [0:length(y)-1];
end

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