How do I make a function that checks the divisibility of a given number, n, by 3, 5, 7, and 11.

I am trying to write a function div - divisibility(n) that checks the divisibility of a given number input n, by 3, 5, 7, and 11 for a hw problem. The problem requires that my output be a logical vector output of 4 elements corresponding to the divisibility by 3, 5, 7 and 11, respectively. For example, the output of divisibility(14) would be [0 0 1 0]. I have figured out how to write a function that gives a single output, but I do not know how to write a function that outputs a logical vector.

All I have so far is:

function div = divisibility(a)

div = rem(a,3)

end

Answer 1

[Star Strider]

This works:

divisibility = @(x) rem(x, [3 5 7 11]) == 0;

div = divisibility(14)

producing:

div =

       0     0     1     0

[Ian Karin]

Thank you so much!

[Star Strider]

My pleasure!

That was actually a fun problem!

[Andrea Guzman]

When you run the function like this, you produce both the div logical array and an ans logical array. How do you get rid of the ans logical array

[Walter Roberson]

the posted code does not produce ans

Answer 2

[Chad Greene]

22 is divisible by 11. The logical command makes all nonzeros into ones and the tilde (~) then takes the not of the logical. What you're left with is a one wherever the remainder is zero.

a = 22; 
div = ~logical(rem(a,[3 5 9 11 44]))