determine how many terms in the series 3k2 where k = 0,1,2,3, .... are required for the sum of the terms, not to exceed 2000. What is the sum for this number of terms?

I'm learning matlab and i want to know how to solve this problem ... if anyone can help ?

determine how many terms in the series 3k2 where k = 0,1,2,3, .... are required for the sum of the terms, not to exceed 2000. What is the sum for this number of terms?

Answer 1

[David Hill]

k=0:20;
y=3*k.^2;%not sure what 3k2 means
c=find(cumsum(y)<2000,1,'last');%number of terms

[siham hammou]

THANK YOU

[Image Analyst]

Looks good to me (same as what I would have done), so you can thank him by clicking the "Accept this answer" to award him "reputation points", unless you want to wait for more answers (but I doubt you'll get any better responses). You could also do it with a for loop and "break" but most people would do it vectorized like David did it.