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Why do I get an infinity number in matrix X2?

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I am using the Jacobi method in matlab but when I run the program the matrix X2 seems to have a problem. I think its something to do with the while loop?
My program in the editor is
A=[2 -1 1; 3 -3 9; 3 3 5];
B=[7; 18; 14];
X1=[1; 0; 0];
s=3;
X2=zeros(3,1);
i=1;
j=i;
X3=rand(3,1);
while X2~=X3
for i=1:s
sum=0;
if X2~=X3
for j=1:s
if i~=j
sum=sum+A(i,j)*X2(j,1);
end
end
X3(i,1)=(1/A(i,i))*(B(i)-sum);
end
end
X2=X3;
X3=ones(3,1);
end
X1
X2
X3
Plsss help me I have to submit this assignment asap

Answers (2)

Jan
Jan on 5 Mar 2022
X3 is growing massively until it reachs Inf. Simply insert some output, e.g. by removing the semicolon from "X2=X3;" to observe this.
This happens, because this is, what the code instructs Matlab to do. I cannot recommend a fixing, because I do not know, what you want to calculate instead.
  1 Comment
Image Analyst
Image Analyst on 6 Mar 2022
@Alexandra Panayiota Gregoriou, Also, don't use "sum" as the name of your variable since it's the name of an important built-in function. Call it "theSum" or something else.

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Torsten
Torsten on 6 Mar 2022
Edited: Torsten on 6 Mar 2022
function main
%A = [2 -1 1; 3 -3 9; 3 3 5];
%b = [7; 18; 14];
%x0 = [1; 0; 0];
A = [4 -1 -1; -2 6 1; -1 1 7];
b = [3; 9; -6];
x0 = [0; 0; 0];
Eps = 1e-8;
x = JacobiSolve(A, b, x0, Eps);
x
A*x-b
end
function x = JacobiSolve(A, b, x0, Eps)
n = length(b) ;
x = zeros(size(x0));
Error = 1;
while Error >= Eps
for i = 1 : n
x(i) = b(i) ;
for j = 1 : n
if j ~= i
x(i) = x(i) - A(i, j)*x0(j) ;
end
end
x(i) = x(i) / A(i, i) ;
end
Error = norm(x-x0, inf);
x0 = x;
end
end
Note that the Jacobi method is not guaranteed to converge for every matrix A.

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