Hello,
I am trying to use xlim to limit my x-axis
h_to_plot = linspace(1,20,20);
horizon = 1:1:20;
quant = 1.64;
mat = [coefficients ses [1:1:20]'];
[~,idx] = sort(mat(:,1));
sortedmat = mat(idx,:);
figure(3)
errorbar(horizon(h_to_plot),sortedmat(h_to_plot,1),quant*sortedmat(h_to_plot,2),'o','Linewidth',2)
hold on
xlim = ([0 20.5])
However, I could not make x-axis starts from 0 to 20.5
Is there any way I could use xlim to extend my x axis to 20.5?
Thanks

 Accepted Answer

VBBV
VBBV on 3 Dec 2021
xlim([0 20.5]) % difference
Difference in using and = between the xlim and parenthesis

5 Comments

Ajay S
Ajay S on 26 Dec 2022
bruh can you please make it a bit more clear
Simon
Simon on 12 Feb 2025
xlim([0 20.5]) is correct
xlim = ([0 20.5]) is incorrect
The command:
xlim = ([0 20.5])
xlim = 1×2
0 20.5000
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creates a variable named xlim. While that variable exists, attempts to call the xlim function in that context will instead be interpreted as an attempt to index into that variable. For example, if I try to then set the limits to the vector [-1 1] using the xlim function, MATLAB will throw an error since there's no such thing as the -1st element of an array in MATLAB:
xlim([-1 1])
Array indices must be positive integers or logical values.

xlim appears to be both a function and a variable. If this is unintentional, use 'clear xlim' to remove the variable 'xlim' from the workspace.
Paul
Paul on 12 Feb 2025
I don't think I've ever seen this error message before idenitfying the ambiguity between the variable and the function. Is that new?
Is there any overhead incurred by Matlab having to determine the xlim is also a function in this case?
Would it also indicate if xlim is some other useful thing, like an .m file or .slx file or a class definition?
This is a common mistake, and future readers should make sure that the variable that they mistakenly created gets cleared, otherwise the error will persist even after the code is fixed.
clear xlim

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on 3 Dec 2021

Commented:

DGM
on 13 Feb 2025

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