Conversion of feet.inch to meter

How to convert a number with 5'.9''(5 feet 9 inch) to meter. I have tried convlength() but here the problem is after decimal it taking the number as unit "feet" not in "inch".

Actullay I have a data vector X = [6.5 5.9 5.9 3.4] where left side of the decimal are in unit "feet" and right side of the decimal are in "inch"

I have tried to create own function which is like this but this is not efficient way as I have to put a comma(,) in bettween two number. Can someone help me out.

function x = conv_feet(feet,inch)
 inch1 = feet*12;
ans_2 = (inch+inch1)*0.0254; % to convert inch scale into meter scale
x = ans_2;
end

[Stephen23]

'Actullay I have a data vector X = [6.5 5.9 5.9 3.4] where left side of the decimal are in unit "feet" and right side of the decimal are in "inch"'

Please show how three feet and eleven inches would be represented in that vector.

"this is not efficient way as I have to put a comma(,) in bettween two number"

Abusing decimal numbers will make this task very inefficient. Better data design is strongly recommended.

[DGM]

Maybe to make the point more clear, is 3.1000 equal to 3' 10.00", or is it 3' 1.000"?

If this vector is actually a string or char vector of numbers, that might be a different story, but if they're numeric, you're in trouble.

[Sudhir Kumar]

I have redisgned my code as follows and i got the answer

function y = conv_feet(x)
   feet_1= floor(x);
   inch = x - feet_1;
   inch = inch*10;
   feet_2 = inch/12;
   ans_2 = (feet_1 + feet_2)*0.3048;
   y = ans_2
end

[Stephen23]

"I have redisgned my code as follows and i got the answer"

I doubt that, because so far you have inconsistent handling of inches. Compare:

x = [5.01,5.09,5.9,5.11]

x = 1×4

5.0100 5.0900 5.9000 5.1100

feet_1= floor(x);
inch = x - feet_1;
inch = inch*10

inch = 1×4

0.1000 0.9000 9.0000 1.1000

Your very poor data design is causing you problems, which your code does not handle.

Answer 1

[Stephen23]

Rather than abusing the definition of decimal numbers, a much better way to store feet and inches is in a matrix:

FI = [6,5;5,9;5,11;3,4] % [feet,inches]

FI = 4×2

6 5 5 9 5 11 3 4

Then your task is trivial using a very basic matrix mulitplication:

M = FI*[12;1]*0.0254 % meter per inch

M = 4×1

1.9558 1.7526 1.8034 1.0160

Better data design -> better code.