Matlab doesn't evaluate derivative of Riemann zeta function
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Hello everyone,
I'm pretty new to Matlab, so please excuse if this is a stupid question.
Yesterday I wrote the following with which I successfully evaluated both the zeta function and its derivative and arrived at a numerical value for c:
syms x
g=zeta(x)
a=subs(g,x,0.49935)
gp=diff(g,x)
b=subs(gp,x,0.49935)
c=b/a
Today, however, I don't know why, typing the same thing I get
g =
zeta(x)
a =
-1.4578
gp =
zeta(1, x)
b =
zeta(1, 9987/20000)
c =
-(1125899906842624*zeta(1, 9987/20000))/1641346078514575,
i.e., id doesn't evaluate the derivative anymore.
I tried it in a different way, too, typing
>> f=sym('zeta(x)');
>> dfdx=diff(f)
dfdx =
zeta(1, x)
>> x=.5;
>> eval(dfdx)
And this is the error I got:
??? Error using ==> zeta
Too many input arguments.
Error in ==> sym.eval at 15
s = evalin('caller',vectorize(map2mat(char(x))));>> f=sym('zeta(x)');
What am I doing wrong? And why did it work yesterday and not today? I would be extremely thankful for any kind of help or support.
Anna
0 Comments
Answers (1)
Anna Klabunde
on 19 Aug 2011
1 Comment
Walter Roberson
on 19 Aug 2011
which -all zeta
might have shown that you had accidentally created a new zeta.m file.
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