Please do not hesitate to correct me if I am wrong. As the images are 3D, optical flow vectors are 3D too. Consequently, each vector has derivatives along three Cartesian coordinates (Ix, Iy and Iz).
Please do not hesitate to correct me if I am wrong. As the images are 3D, optical flow vectors are 3D too. Consequently, each vector has derivatives along three Cartesian coordinates (Ix, Iy and Iz).
Hello, your scripts are very helpful, but I have a question for the sub-function 'imageDerivatives3D'. I don't quite get why the derivatives Ix, Iy and Iz are calculated using the two images. Could you please explain it for me or offer a ref? Thank you very much.