How do I extract non sequential rows of a matrix without using a for loop?

I have a very large matrix (m1), and I want to create a new matrix (m2) using certain rows of m1. The list of rows I want is contained in a 1xN matrix called "list". Naively, I would expect the command to be

m2 = [m1(list,:)]

However, matlab will not accept a matrix as an index. (I receive the error "Subscript indices must either be real positive integers or logicals.")

Any help would be appreciated.

For context: The matrix m1 is too large for me to attempt this exercise by hand -- it contains 100000 rows. Also, there is no obvious mathematical relationship among the entries in "list".

[Matt Kindig]

Normally you can do this. I would expect that list either contains a) non-integers, or b) elements that are less than 1.

Try round()-ing list first, i.e.,

m2 = m1(round(list),:)

[Ryan Melvin]

List contains only integers from 0 to 99990.

[Ryan Melvin]

Actually, you were correct. List was an output from a program that starts counting from 0; whereas, matlab's indices count from 1. I added 1 to every member of list, and now things work as expected. Thank you.