Distance between a points in 2D and 3D matrix in Matlab

I want to find the distance between a point in a 2D matrix and a point in a 3D matrix. My 2D matrix has the information (num, k) and my 3D has the information (X,Y,num). I would like to use the distance equation, but everytime I try I one form or another I get an error because of dimensions. Is there any way to do this?

In 2D I can compute the information using:

for n = 1:3 ...
for i = 1:3 
    d(n,i) = sqrt((g(i,1)-A(n,1))^2+(g(i,2)-A(n,2))^2);
    dd(n,i) = double(d(n,i));
end
end

In 3D I tried to compute the information using

for n = 3...
for i = 1:3 
    d(n,i) = sqrt((g(i,1)-A(n,1,:))^2+(g(i,2)-A(n,2,:))^2);
    dd(n,i) = double(d(n,i));
end
end

I only started using Matlab recently so I am assuming that if I use a : in the third column of the 3D A matrix, this will "disregard" the 3rd column.

I would appreciate it if someone could lead me in the right direction as to syntex or a basic explanation of the math if I am wrong with it as well.

[Matt J]

Wouldn't d have to be 3-dimensional in the 3D case? You'r e indexing it 2-dimensionally d(n,i).

Answer 1

[Matt J]

This will output ann array indexable as d(i,n,num)

 f=@(a,b) (a-b).^2;

 d=bsxfun(f,  g(:,1), A(:,1,:) ) + bsxfun(f,  g(:,2), A(:,2,:) );
   d=sqrt(d);

 dd=double(d);

[Victoria Chang]

Hi, thanks for the reply! I tried this method on my code. However, I got an error using bsxfun.

Error using bsxfun. Non-singleton dimensions of the two input arrays must match each other.

[Matt J]

You might need to do

 d=bsxfun(f,  g(1:3,1).', A(1:3,1,:) ) + bsxfun(f,  g(1:3,2).', A(1:3,2,:) );