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operation array in cell
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i have 2 matrix A and B and cell Z with 13*13 blocks. each blocks have 8*8 pixel.
A=rand(13,13,8,8);
B=rand(13,13,8,8);
i want to process value A and B with each blocks in cell Z.
XY = (Z*A)+B
example, value at A if you see at workspace, start with val(:,:,1,1), there's will be 169 value of A. each value will be process with every blocks of Z to get XY. same with matrix B. total blocks of Z is same with total value of A and B in val {:,:,1,1}.
specificly,
XY{1,1}=Z{1,1}.*A{1,1,1,1} + B{1,1,1,1},
XY{1,2}=Z{1,2}.*A{1,2,1,1}+B{1,2,1,1} until the whole blocks of Z.
3 Comments
Answers (1)
Andrei Bobrov
on 5 Mar 2013
Edited: Andrei Bobrov
on 5 Mar 2013
A1 = permute(A,[3 4 1 2]);
B1 = permute(B,[3 4 1 2]);
XY = Z;
for ii = 1:size(Z,1)
for jj = 1:size(Z,2)
XY{ii,jj} = Z{ii,jj}.*A1(:,:,ii,jj) + B1(:,:,ii,jj);
end
end
ADD variant
Zn = cat(3,Z{:});
s = size(A);
A1 = reshape(permute(A,[3 4 1 2]),s(3),s(4),[]);
B1 = reshape(permute(B,[3 4 1 2]),size(A1));
XY = reshape(num2cell(Zn.*A1+B1,[1 2]),size(Z));
7 Comments
Jan
on 6 Mar 2013
@Internazionale: It would help, if you post the code you are using and a complete copy of the error message. Andrei hast posted two different solutions, and you could potentially have modified one of them, e.g. by a typo. We cannot reliably guess the cause of the error on your computer, so it is your job to explain the circumstances.
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