indices of intersection points of two logical arrays

how can I find the indices of the intersection points of a binary image with a logical array

this is the code

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f2= imread('anyBinaryImage');
norm2 = normalization(f2,128,128); % normalization function
f3= zeros(size(norm2));
a = ones(2,80);
f3(10:11,1:80) = a;
[g, k, c]= intersect(norm2,f3,'rows');

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but I got empty matrix, even though there are lots of intersection points between the image and the array

g =
   Empty matrix: 0-by-128
k =
   Empty matrix: 0-by-1
c =
   Empty matrix: 0-by-1

what should I do ?

[Roger Stafford]

To get entries in 'g', entire rows of 'norm2' would have to either consist of all ones or all zeros. Is that what you expect "lots of" in 'norm2'?

[Walter Roberson]

The f3 you construct is not a logical array. zeros() and ones() create numeric arrays, not logical arrays. Initialize with false(size(norm2)) instead of zeros()

[Amani]

thank you soooooo much for clarifying

Answer 1

[Image Analyst]

Try it this way:

% Find pixels in both binary images:
intersectionImage = f2 & f3;

% Now get the rows and columns of the intersecting pixels
% (for some unknown, unspecified, and probably unnecessary reason):
[rows columns] = find(intersectionImage);

Are you sure you really need the rows and columns of the intersections? I'd say that most likely you don't need them at all. The intersectionImage is enough to do whatever you're going to do.

[Amani]

thank you very much , it works I'm working on handwriting recognition, so I'm trying to find the intersections with the baseline

[Azzi Abdelmalek]

Amani, When the answer helps, you have to click on [accept this answer]. Now, I did it at your place