no of bits increases after decimal to binary conversion

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I performed
a =
5
-5
b=dec2bin(2^4+a)
b =
10101
01011
I have given 4 bits but why my output gives 5 bit value,also for 5 why may MSB is 1`,for -5 why it is 0,also if i perform
a=0;
b=dec2bin(2^4+a)
b =
10000
In this why my MSB is 1

Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 26 Nov 2012
Edited: Azzi Abdelmalek on 26 Nov 2012
2^4+5 requires at least 5 bits
If you want to represent a with 4 bits
b=dec2bin(a,4)
also, to use dec2bin(a), a must be non negative integer
  3 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 26 Nov 2012
Yes, That what I said above, to represent signed binary number use 2's complement representation http://en.wikipedia.org/wiki/Two%27s_complement
Pat
Pat on 26 Nov 2012
Azzi can u please provide me an example ,i understood concept ,but dont know how to start with

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