Periodogram PSD vs FFT PSD

2 views (last 30 days)
Terry
Terry on 5 Oct 2012
When power scaling the magnitude of the output from an FFT one could use the following scaling which equivocates the psd of the FFT to the MSE of the time series:
PSD0=(abs(x)/N)^2
PDSi=2*(abs(x)/N)^2 for i=1, 2, …n/2+1
The MatLab function ‘periodogram’ returns PSD values that sum to twice the MSE of the time series (each PSD value is twice the FFT value). Why is that? Both analysis were done with no windowing.
  1 Comment
Honglei Chen
Honglei Chen on 5 Oct 2012
Hi Terry, could you show the comparison code?

Sign in to comment.

Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!