Find distance between point (1,3,1) and plane 3(x-2)+2(y-1)-3(z-1)=0

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sangeetha
sangeetha on 6 Aug 2012
can't seem to find the commands for this.

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Accepted Answer

Andrei Bobrov
Andrei Bobrov on 6 Aug 2012
fp = @(x)(x(:).' - [2, 1, 1])*[3;2;-3]; % your plane
x0 = [1,3,1]; % your point
d = fp(x0)/norm([3;2;-3]) ; % your distance

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