Get coeffients of symbolic expression

I have a set of equations (derv_alpha) that I have arrived at by differentiating an expression and setting it to zero.

N=3; alphavec = sym('alpha',[1 N]); %N can take any value
derv_alpha = [ 0, 2*alphavec(3) - 2*alphavec(2) + 2, 2*alphavec(2) - 4*alphavec(3)];

Now I need to solve these simultaneous equations and come up with answers for alpha2, alpha3...alphaN. i.e. alphavec(2), alphavec(3)...alphavec(N).

I am trying to put this in matrix form A*x=b and solve for x. Is it possible? If so, HOW CAN I GET THE COEFFICIENTS OF EACH VARIABLE?

The solution will have to be irrespective of the position of the variable in the expression.

I did a quick search. collect() doesnt work. i dont think sym2poly can be used

OR, is there a better way to do it when working with symbols?

I am doing my first program using symbols this week and appreciate any help. Thanks again.

Answer 1

Generally,

solve(derv_alpha, alphavec)

However, derv_alpha(1) is the constant 0 and not an expression in the alpha variables, so the set of three equations in derv_alpha, in three variables, is really only two equations in three variables, which you aren't going to be able to solve for. This is going to be a problem even if you express as A*x=b

alpha1 isnt zero. it needs to be solved for after alpha2 and alpha3. I editted the code to remove alpha1.

N=3; alphavec = sym('alpha',[1 N]); %N can take any value
derv_alpha = [2*alphavec(3) - 2*alphavec(2) + 2, 2*alphavec(2) - 4*alphavec(3)];
derv_alpha=simplify(derv_alpha);
alpha_sol=zeros(1:N);
alpha_sol(2:N)=solve(derv_alpha, alphavec(2:N))

last line gives this warning

    "Warning: 4 equations in 2 variables." %where did it get 4 equations??

Here I want to solve alpha2 through alphaN. I will input alpha1 later.

Back to my earlier question - is there a way to get the coefficients?

Thanks again ps- i figured out how to format in the post :)

I am now completely lost as to what you are doing. What coefficients do you want to get? The ‘coeffs’ function will give you the coefficients, however it has to know the variables or expressions you want the coefficients of.

Meanwhile:

          % alpha_sol=zeros(1:N);
          % alpha_sol(2:N)=solve(derv_alpha, alphavec(2:N))        
          alpha_sol_12 = solve(derv_alpha(1) == 0, alphavec(2))
          alpha_sol_13 = solve(derv_alpha(1) == 0, alphavec(3))
          alpha_sol_22 = solve(derv_alpha(2) == 0, alphavec(2))
          alpha_sol_23 = solve(derv_alpha(2) == 0, alphavec(3))

These produce:

alpha_sol_12 =

alpha3 + 1

alpha_sol_13 =

alpha2 - 1

alpha_sol_22 =

2*alpha3

alpha_sol_23 =

alpha2/2

Is this what you want to do?

I initially put that into a loop, but the Symbolic Math Toolbox objected and I don't have the energy tonight to argue with it.

Thanks, but at this point, I want numerical solutions for the alpha's. in this case alpha2=2; alpha3=1;

derv_alpha=[ 2*alpha3 - 2*alpha2 + 2, 2*alpha2 - 4*alpha3]

The coefficients I want are for alpha2, alpha3 and constants. for equations

2*alpha3 - 2*alpha2 + 2==0
2*alpha2 - 4*alpha3 ==0

answer I am looking for would be

coeff_matrix=[-2 3 2; 2 -4 0]

So that I can solve for alpha2 and alpha3 by A*x=B form

alpha_solution = [-2 3;2 -4]\[2 0]; %something like this.

Thanks again and yes, acceptable that a fight with MATLAB at midnight isnt the best thing :)

With regard to four equations: if your code read

derv_alpha = [2*alphavec(3) -2*alphavec(2) + 2, 2*alphavec(2) -4*alphavec(3)];

with no space after the '-', then the '-' would be interpreted as unary minus and the space would be interpreted as the end of the term in the list. [A - B] is one expression but [A -B] is two, A and -B . You can ensure your desired groupings by adding ()

Thanks. It's an output from another line of code which is the partial derivative of an expression. The spaces are what MATLAB gives and frankly, I was wondering about it myself. Thanks

does anyone know how to do this? Thanks