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Why did I receive this error with inline

Asked by Hassan on 5 Jul 2012

I have an inline object defined in the following manner (Part of code):

```for o= 1 : 6
f = inline('min(x.+d(o,5),-x.+d(o,3))');
%%where d is a matix
.
.
for k= 1 : 3
.
.
val (k)=f(Pbest (k,1));
end
end
```
```Error using inline/subsref (line 13)
Not enough inputs to inline function.
```

1 Comment

Walter Roberson on 6 Jul 2012

I recommend you use anonymous functions instead of inline.

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3 Answers

Answer by the cyclist on 5 Jul 2012

The way you have defined you inline function, it is going to contain the variable o, rather than replacing it with the loop's value of o.

I think what you want instead is this:

```f = inline(['min(x.+d(',num2str(o),',5),-x.+d(',num2str(o),',3))'])
```

Also, o is a terrible name for a variable. ;-)

0 Comments

Answer by Honglei Chen on 5 Jul 2012
Edited by Honglei Chen on 5 Jul 2012

I see several issues:

1. You should use + instead of .+
2. The error is due to the fact that there are three variable in your function: x,d, and o. You should define them. As is, MATLAB thinks that d is a function but then there should be two inputs and you invoked it with only one input.

Below is a working example:

```f = inline('min(x+d(o,3),-x+d(o,3))','x','o','d')
f(1,2,magic(5))
```

0 Comments

Answer by Star Strider on 5 Jul 2012

First, you only need to define your 'inline' function once, ideally near the beginning of your code. Put it before your loop.

Second, it needs to know what you want it to do, so you have to specify your arguments to it:

`   f = inline('min(x+d(o,5), -x+d(o,3))', 'x', 'd', 'o');`

I have no idea what you want to do with your 'val(k) = ...' assignment, since it doesn't seem to match what you want 'f' to do.

Third, in my experience, it's not necessary to use the '.' operator with '+' and '-' since they operate element-wise anyway. It's only necessary to use it with '*', '/', and '^'.

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