A the surface x->-10:10, y->-10:10, z=0 to a plot of a curve in 3d (using plot3 in Matlab 2014b)?
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I have a curve in 3-dimensions, corresponding to
xx=0:9; yy=[-5:0 -1:-1:-4]; zz=[1:5 4:-1:0]; plot3(xx,yy,zz,'-o');
I wish to plot a semi-transparent surface corrseponding to x->-10:10, y->-10:10, z=0
How do I add this to the plot? I use Matlab 2014b.
In addition, is there a way to plot such that the axes and their origin will show up in the middle of the figure, and not in the sides?
Thank you!
1 Comment
jonas
on 21 Oct 2018
Please do not spam your question. If anything, it makes some people (like me) less inclined to help.
Accepted Answer
Star Strider
on 21 Oct 2018
Try this:
xx=0:9;
yy=[-5:0 -1:-1:-4];
zz=[1:5 4:-1:0];
figure
plot3(xx,yy,zz,'-o');
hold on
patch([-10 10 10 -10], [10 10 -10 -10], 'r', 'FaceAlpha',0.2)
hold off
grid on
‘... is there a way to plot such that the axes and their origin will show up in the middle of the figure, and not in the sides?’
Not in R2014b. I believe that was added in R2017b.
4 Comments
jonas
on 21 Oct 2018
Edited: jonas
on 21 Oct 2018
Just to add:
"In addition, is there a way to plot such that the axes and their origin will show up in the middle of the figure, and not in the sides?"
ax = gca;
ax.ZRuler.FirstCrossoverValue = 0;
ax.ZRuler.SecondCrossoverValue = 0;
ax.XRuler.FirstCrossoverValue = 0;
ax.XRuler.SecondCrossoverValue = 0;
ax.YRuler.FirstCrossoverValue = 0;
ax.YRuler.SecondCrossoverValue = 0;
box on
Star Strider
on 21 Oct 2018
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