Converting netCDF time (hours since 1-1-1 00:00:00.0) to actual date

Does anyone out there know how to do the conversion I have noted above? datestr() and datenum() are not helping much. For example:

a = time(1,1);
a = 17298624;
b = datestr(a);
b = 08 - Jan - 7362

When the data is a monthly mean from Jun 1974 with a time step of per month. The files are from www.esrl.noaa.gov.

Thanks!

[yaxin sun]

This friend,I have some similar problems with yours ,I also want to know that how to deal with this problem about you .

Answer 1

[Walter Roberson]

Divide "a" by 24 as it is hours but datestr() needs days. And then add 367 to the result in order to compensate for the time base of 1-1-1 instead of datestr()'s time base of 0-0-0 . (datestr thinks year 0 was a leap year.)

[Clifford]

Thank you!

Is it still correct even though the dates come out as the 3rd of each month instead of the 1st?

[Walter Roberson]

Guess it should be 365 then...

[Mian]

Thank you, it also helped me

[Walter Roberson]

In modern times I would say,

datetime(1,1,1) + hours(NumberFromNetCDFFile)