How can I sort data in a loop with an if selection structure?
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Michael Toney
on 21 Oct 2014
Answered: Mohammad Abouali
on 22 Oct 2014
Say if I have a vector of numbers grades = [84;62;91;85;73;69;44;90;82] and I want to sort them like grades, A being 90-100, B being 80-89, C being 70-79, D being 60-69, and F below 60. I want to use a loop with an if selection structure to sort them. But when I run my code only my F values show up with a column vector of zeros and 1's being in place of the values that are true for the F grades. Any suggestions on how to correctly do this?
4 Comments
Amit Varshney
on 21 Oct 2014
You do need the 'if' and 'elseif' statements. Try the following
A2 = grades(find(grades >= 93))
A_m2 = grades(find(grades >= 90 & grades < 93))
ans so on..
Accepted Answer
Mohammad Abouali
on 22 Oct 2014
Another way of coding without all these if then classes is this:
% Generating some random grades
Grades_Numeric=randi(100,[10,1]);
levels=[60,70,77,80,83,87,90,93,97];
GradesClasses={'F';'D';'C';'C+';'B-';'B';'B+';'A-';'A';'A+'};
% now getting each grade falls in what category
Grades_Mask=imquantize(Grades_Numeric,levels);
[Grades_Mask Grades_Numeric]
ans =
2 66
1 50
4 78
3 72
8 91
7 90
1 34
2 70
1 20
1 4
%retrieving the categorial grades.
GradesClasses(Grades_Mask)
ans =
'D'
'F'
'C+'
'C'
'A-'
'B+'
'F'
'D'
'F'
'F'
The good thing about this approach is that if you want to change your levels and classes you don't need to write any code, (may be not in this case) but in cases that these classes and levels are not decided they can be easily passed as an input to a function.
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