Comparing a logical matrix and a numerical matrix?
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I want to make a function that takes in as input a matrix (orig) and a logical matrix (mask). If the logical at a certain index is 1, I want the value in that same index for the orig equal to what it is. If it is zero, I want the orig to be the value in that index divided by 4.
function [masked] = maskImage(orig, mask)
For example, if
orig = [45 32 145; 88 33 203; 33 231 40] and
mask = [1 0 1; 1 1 0; 0 1 1], then orig (masked) would become
[45 32/4 145; 88 33 203/4; 33/4 231 40].
Any help is appreciated.
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Answers (3)
Roger Stafford
on 20 Oct 2014
Assuming 'mask' really is a logical array the same size as 'orig' do:
orig = mask.*orig+(~mask).*orig/4;
Otherwise if 'mask' is actually numerical 1's and 0's do:
orig = (mask==1).*orig+(mask~=1).*orig/4;
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