Can someone check my code?

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Bri
Bri on 15 Oct 2014
Answered: siham boujrad on 11 May 2019
I am suppose to create a function m file called myminimum(f,a,b) which takes three inputs:
f: A function handle.
a: A real number.
b: A real number.
Note: You may assume that f(x) is a quadratic function and that a < b.
Does: Finds the minimum value of f(x) on [a, b] keeping in mind that this may occur either at the
critical point (if the critical point is in [a, b]) or at one of the endpoints. You’ll probably
want to use some if statements to check cases.
Returns: The minimum value of f(x) on [a, b].
Here is my code:
function m=myminimum (f,a,b);
syms x;
y=subs(f(x),a);
z=subs(f(x),b);
w=subs(diff(f(x)),0);
m=min(y,z,w);
end
It keeps returning an error. The error says "MIN with two matrices to compare and a working dimension is not supported." Can someone tell me how to fix my code?
Here is some sample data and the correct answers to the same code.
a= myminimum(@(x) x^2+1,-3,2)
a = 1
a = myminimum(@(x) x^2+6*x-3,-2,0)
a = -11
a = myminimum(@(x) -2*x^2+10*x,3,8)
a = -48

Accepted Answer

Star Strider
Star Strider on 15 Oct 2014
  7 Comments
Star Strider
Star Strider on 17 Oct 2014
I took the essence of your code outside of the function (exactly as I posted it) because I run everything I test on MATLAB Answers in a test script file that doesn’t allow function definitions, so break worked. Replace break with return and all should be well.
Star Strider
Star Strider on 17 Oct 2014
My pleasure!

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More Answers (2)

siham boujrad
siham boujrad on 11 May 2019
%This program computes to calculate the Total Resistance (or Impedance) for Series or Parallel Circuit.
R1=input('Enter the value of R1'); %ohms
R2=input('Enter the value of R2'); %ohms
R3=input('Enter the value of R3'); %ohms
R=[R1,R2,R3];
RTs=sum(R);
RTp=1/sum(1./R);
If RTs>=5 & RTs<25
fprintf('Resistors are in series and R_Total = %7.2f ohms \n',RTs)
elseif RTp>0 & RTp<=1
fprintf('Resistors are in parallel and R_Total = %7.2f ohms \n',RTp)
else disp('Error')
endif

siham boujrad
siham boujrad on 11 May 2019
plz i need someone to check the code for me. Thank you

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