I want to store the digits after the decimal point of the numbers stored in an array. How do I do it?

 For eg. If one of my number is 1.23456789 then I want '234' out of it. I want only the 3 digits after the decimal point. Can you help me?

[Stephen23]

It is not completely clear: do you want a character array (e.g. '234' ) or a numeric vector of the digits (e.g. [2,3,4] ) as the output?

[Image Analyst]

He said the character string, but my guess is that he really wants a single 3 digit integer (or double) just like what dpb's code give.

Answer 1

[Stephen23]

To get the digits in a scalar numeric:

>> x = 1.23456789;
>> N = 4;
>> n = fix(rem(x,1)*10^N)
n = 2345

then to convert this to a string:

>> s = sprintf('%.0f',n)
s = '2345'

and finally to get the digits in a numeric vector:

>> v = s-'0'
v = [2,3,4,5]

[Nilu Desai]

Thank you so much. It helped. I exactly wanted this.

[Stephen23]

An alternative way to generate a string and numeric vector of the decimal digits:

>> N = 4; % how many digits
>> A = 1.23456789;
>> B = sprintf('%.*f',N,mod(A,1)-mod(A,10^-N));
>> B(3:end)
ans = '2345'
>> B(3:end)-'0'
ans = [2,3,4,5]

Answer 2

[dpb]

   fix(rem(x,fix(x))*1000)

[Nilu Desai]

Hey.. thank you for the help But I need only the digits after the decimal.. Using your help gives me the whole number with precision upto 3 digits.

[José-Luis]

No, it doesn't.

[Andrew Reibold]

lol @ the simple: "No, it doesn't"

It doesn't for me either