Find all values in an array neighbored on both sides by NaN.
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Chad Greene
on 24 Sep 2014
Commented: Chad Greene
on 24 Sep 2014
I have an array that looks like this:
A = [1 2 4 2 NaN 2 4 NaN 6 NaN NaN 9 5 NaN];
I would like to find all values in A that have a NaN immediately adjacent on both sides. In the example above, the only value that meets this criteria is the 6. I can do it in a loop like this:
ind = false(size(A));
for n = 2:length(A)-1
if isnan(A(n-1)) && isnan(A(n+1))
ind(n)=true;
end
end
Is there a more elegant way to do this?
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Accepted Answer
Sean de Wolski
on 24 Sep 2014
A = [1 2 4 2 NaN 2 4 NaN 6 NaN NaN 9 5 NaN];
A(conv(double(isnan(A)),[1 0 1],'same')==2)
2 Comments
Sean de Wolski
on 24 Sep 2014
Edited: Sean de Wolski
on 24 Sep 2014
Note, the for-loop is plenty elegant. It could be made more elegant by calling isnan once and then indexing into it on each iteration.
idx = isnan(A)
n = numel(A);
for ii = 1:n-2
if idx(ii) && idx(ii+2)
A(ii+1)
end
end
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