Storing values from a loop into an array

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Coding:
for t = 1:24
OT(t,1) = (((Tmax + Tmin)/2)+((Tmax - Tmin)/2)*sin(((t - 9)/12)*PI));
ST(t,1) = OT(t)-5;
B(5,1) = (-1)*Ae*(Hco*ST(t,1) + Qse(t,1));
B(10,1) = (-1)*Aw*(Hco*ST(t,1) + Qsw(t,1));
B(15,1) = (-1)*As*(Hco*ST(t,1) + Qss(t,1));
B(20,1) = (-1)*An*(Hco*ST(t,1) + Qsn(t,1));
B(27,1) = (-1)*Ar*(Hcr*ST(t,1) + Qsr(t,1));
B(28,1) = (-1)*(Qse(t,1)*Awe + Qsw(t,1)*Aww + Qss(t,1)*Aws);
B(29,1) = (-1)*(Qt(t,1))-(V*ACH*RHO*CP*1000*OT(t,1));
X = A\B;
end
I want to be able to store the values of the X matrix (29,1) of each interation into an a table of (29,24) so that i can plot the results over hour of the day.. each iteration represents the hour of the day.
Please Help!!

Accepted Answer

Star Strider
Star Strider on 23 Sep 2014
You need to subscript it so that the columns rather than the rows update:
X(:,t) = A\B;
  3 Comments
Joshua
Joshua on 23 Sep 2014
One MOre question, How would you Plot slected rows from the X(:,t) matrix?
Star Strider
Star Strider on 23 Sep 2014
Edited: Star Strider on 23 Sep 2014
My pleasure!
If you want to plot row n, define n and then plot it against t as:
n = 5;
t = 1:24;
figure(1)
plot(t, X(n,:))
if you want to plot more than one at a time, create n as a vector:
n = [3 5 7];
figure(2)
plot(t, X(n,:))
You could substitute the numbers directly (for instance X(5,:)) instead of using n, but I prefer using the variable in the event I want to use n elsewhere in the plot code. (I also number each plot with figure so I don’t overwrite them with subsequent plots. This is my personal preference but is not required.)

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