Reduce 3D array by removing NaN elements
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Hi !
I ask you for help in Matlab in order to reduce a 3D array. In column there is three numbers (X,Y,Z coordinates) and each row corresponds to a different point. But these points have to respect a certain condition, otherwise three NaN are stored instead of the coordinates. The third dimension correspond to the time evolution of the coordinates stored in the 2D array.
For exemple:
A(:,:,1) =
1 2 3
NaN NaN NaN
NaN NaN NaN
A(:,:,2) =
NaN NaN NaN
1 2 3
NaN NaN NaN
A(:,:,3) =
NaN NaN NaN
NaN NaN NaN
NaN NaN NaN
If I try:
A(any(any(isnan(A),3),2),:,:) = [];
I get:
Empty array: 0-by-3-by-3
Or I would have:
A(:,:,1) =
1 2 3
NaN NaN NaN
A(:,:,2) =
NaN NaN NaN
1 2 3
A(:,:,3) =
NaN NaN NaN
NaN NaN NaN
The array is reduced but the shape is the same and I don't lose informations.
Thank your for your help and have a nice day !
2 Comments
the cyclist
on 25 Aug 2014
What exactly do you want to get rid of? Any row in which all time slices are NaN?
Accepted Answer
the cyclist
on 25 Aug 2014
Edited: the cyclist
on 25 Aug 2014
Maybe you meant all() instead of any()?
idxToRemove = all(all(isnan(A),3),2);
A(idxToRemove,:,:) = []
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