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How can I make struct with existing variables?

Asked by Giorgi on 22 Aug 2014 at 11:53
Latest activity Edited by Matt J on 22 Aug 2014 at 14:21

Hi all, Well i have some variables for example alfa, beta and gama, Now I want to make structure that will contain these variables. Can someone give me a code or function with which i will be able to do it.

0 Comments

Giorgi

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4 Answers

Answer by Matt J on 22 Aug 2014 at 12:27
Edited by Matt J on 22 Aug 2014 at 12:28
Accepted answer

Using structvars ( Available here ).

>> clear
>> a=1; b=2; c=3;
>> s=whos;
>> C=cell2struct({s.name}.',{s.name})
C = 
      a: 'a'
      b: 'b'
      c: 'c'
>> structvars(C,0); %copy/paste the output below to the command line
ans =
C.a = a;    
C.b = b;    
C.c = c;   

3 Comments

Giorgi on 22 Aug 2014 at 12:48

First of all thanks for your activity and help now well I folloew your code but when I write structvars(C,0) it says Undefined function 'structvars' for input arguments of type 'struct'.

Adam on 22 Aug 2014 at 13:03

Did you follow Matt J's 'Available here' link and add the downloaded location to your path?

Matt J on 22 Aug 2014 at 14:13

Though I don't really recommend it, you could also do

>> eval(structvars(C,0).'); C
C = 
      a: 1
      b: 2
      c: 3
Matt J
Answer by Matt J on 22 Aug 2014 at 12:29
Edited by Matt J on 22 Aug 2014 at 12:40
 >> save tempFile *
 >> S=load('tempFile');

0 Comments

Matt J
Answer by Adam on 22 Aug 2014 at 12:02
Edited by Adam on 22 Aug 2014 at 12:04
myStruct.alfa = alfa;
myStruct.beta = beta;

etc.

Or

myStruct = struct( 'alfa', alfa, 'beta', beta );

4 Comments

Adam on 22 Aug 2014 at 12:17

Is it every variable in your workspace or just some subset? If you can create a cell array of all the variable names then you can also use that with an equivalent cell array of the values of each variable to pass to struct.

Giorgi on 22 Aug 2014 at 12:26

Well as you say in txt file I have all variable names, so I measured its length and use cycle here is a code but it does not work any ideas?

a=length(txt(1,:));
for i=1:a
mystruct=struct(txt(1,i),[txt{1,i}]);
end
Adam on 22 Aug 2014 at 13:04

I could try to give some help further along this line, but I think potentially either of Matt J's solutions would work better so unless neither of them do I'll leave it.

Adam
Answer by Guillaume on 22 Aug 2014 at 12:04
s = struct('alpha', alpha, 'beta', beta, 'gamma', gamma);
doc struct

2 Comments

Giorgi on 22 Aug 2014 at 12:12

Well that is fine but if i have more than 30 variables should I write it manually? The problem is that I cant write a code with which it automaticly will assign all variables

Guillaume on 22 Aug 2014 at 13:03

You could dynamically create a structure with 30 field names that are the names of the variables, however I would urge to think whether it's really what you want. How are you going to then use that structure if the field names are created arbitrarily. I would advise against this as your code may easily break in the future because a hardcoded field is not there anymore.

If that's really what you want to do, then structvars from the other answer (you have to download it), or the following function will do it:

function s = variables2struct(varargin)
  s = struct;
  for var = 1:nargin
    s.(genvarname(inputname(var), fieldnames(s))) = varargin{var};
  end
end
Guillaume

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