ERROR USING VERTCAT HELP PLEASE
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I keep getting this error
"Error using vertcat Dimensions of matrices being concatenated are not consistent."
P=(100:100:1000);
for i=1:P
D = [1 0 0 -0.857 -0.832 -0.812;
0 1 0 0.286 0.555 0.542;
0 0 1 0.429 0 -0.217;
0 0 0 0 0 0.0379;
0 0 0 -0.1286 0 0.1218;
0 0 0 0.0857 0.1664 0.1625;];
E= [0;
P;
0;
0.15.*P;
0;
0.3.*P;];
X=D\E;
end
2 Comments
José-Luis
on 14 Jul 2014
Please type in your code instead of pasting an image. It would make it easier for people to help you.
Accepted Answer
James Tursa
on 14 Jul 2014
Edited: James Tursa
on 14 Jul 2014
It is unclear what you are trying to do with the loop. P is a vector [100 200 ... 1000], so the for loop indexing i=1:P doesn't seem to make sense. And then inside your matrix building you have scalars mixed in with this P vector for the concatenation, hence the error. Did you mean to do this instead?
P=(100:100:1000);
for k=P
D = [1 0 0 -0.857 -0.832 -0.812;
0 1 0 0.286 0.555 0.542;
0 0 1 0.429 0 -0.217;
0 0 0 0 0 0.0379;
0 0 0 -0.1286 0 0.1218;
0 0 0 0.0857 0.1664 0.1625;];
E= [0;
k;
0;
0.15.*k;
0;
0.3.*k;];
X=D\E;
end
2 Comments
James Tursa
on 14 Jul 2014
Option 1) Preallocate X and save each iteration in X, e.g.
P=(100:100:1000);
X = zeros(6,numel(P));
m = 1;
for k=P
D = [1 0 0 -0.857 -0.832 -0.812;
0 1 0 0.286 0.555 0.542;
0 0 1 0.429 0 -0.217;
0 0 0 0 0 0.0379;
0 0 0 -0.1286 0 0.1218;
0 0 0 0.0857 0.1664 0.1625;];
E= [0;
k;
0;
0.15.*k;
0;
0.3.*k;];
X(:,m)=D\E;
m = m + 1;
end
Option 2) Do all of the calculation in one fell swoop without a loop. E.g.,
P=(100:100:1000);
D = [1 0 0 -0.857 -0.832 -0.812;
0 1 0 0.286 0.555 0.542;
0 0 1 0.429 0 -0.217;
0 0 0 0 0 0.0379;
0 0 0 -0.1286 0 0.1218;
0 0 0 0.0857 0.1664 0.1625;];
E = zeros(6,numel(P));
E(2,:) = P;
E(4,:) = P*0.15;
E(6,:) = P*0.3;
X=D\E;
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