how to make a vector of 30 rows 1 column with increasing values of elements
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I want to make a matrix of 30 rows 1 column like [1;1;1;1;1;2;2;2;2;2;3;3;3;3;3;4;4;4;4;4;5;5;5;5;5;6;6;6;6;6] please anyone help.
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Star Strider
on 23 Jun 2014
Edited: Star Strider
on 23 Jun 2014
This works:
V1 = 1:6;
M = repmat(V1', 1, 5)';
V2 = M(:) % Output Vector
7 Comments
Star Strider
on 26 Jun 2014
I do not see a pattern in:
[1;1;1;1;2;2;2;2;2;2;3;3]
so I do not know what to suggest as to how to generate it. If it is random in the length of each value, use the randi function to determine the number of each integer:
Vlen = 10;
V1 = 1:Vlen;
V2 = [];
for k1 = 1:Vlen
V2 = [V2; k1; repmat(k1, randi(9), 1)];
end
Change Vlen to create the approximate length of the vector you want. If you overshoot, simply truncate it to the length you need.
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