how shall i keep the particular position of a column of a matrix to to repeat for all other columns?????

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this is a code ::::
a1=rand(10,10);
a=a1(:,1);
a=a';
c=ceil(a); %% when err=1 err=1;
maxValueRowWise=max(a');
for k=1:length(maxValueRowWise)
c(a==maxValueRowWise(k))=0;
end
% disp('For err=1')
% c
%%when err=2
err=2;
s=sort(a,2);
twoMaxValueRowWise=s(:,end-1:end);
for k=1:numel(twoMaxValueRowWise)
c(a==twoMaxValueRowWise(k))=0;
end
% disp('For err=2')
% c
%%when err=3
err=3;
s=sort(a,2);
ThreeMaxValueRowWise=s(:,end-2:end);
for k=1:numel(ThreeMaxValueRowWise)
c(a==ThreeMaxValueRowWise(k))=0;
end
% disp('For err=3')
% c
%%when err=4
err=4;
s=sort(a,2);
ThreeMaxValueRowWise=s(:,end-3:end);
for k=1:numel(ThreeMaxValueRowWise)
c(a==ThreeMaxValueRowWise(k))=0;
end
disp('For err=')
c
[y]=find(c==0)
here y indicates the position of error now in a1 the y row element every node will give wrong answer if by round(a1) is 1 than 0 else 1.
this whole process will be running for 10 times and in every iteration this y wont change and it will give error. plz plz plz help me out....
  3 Comments
suchismita
suchismita on 18 Jun 2014
ya here i have set maximum values but can i set as in between values from 0.8 to 0.3.....4 highest values will be taken....?????
suchismita
suchismita on 18 Jun 2014
with maximum value first i want to check i can do this or not...than in my assignment i have to do for minimum and in between 0.8 to 0.3

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Accepted Answer

Andrei Bobrov
Andrei Bobrov on 18 Jun 2014
[~,jj] = sort(a(:),'descend');
y1 = sort(jj);
y = y1(1:err);
  1 Comment
suchismita
suchismita on 18 Jun 2014
can you explain it plzzzz... in a1 if the error positions are 2 8 9 10 then in a(2,:),a(8,:),a(9,:),a(10,:) will say as 0. (only in first column checking for maximum value is done not in others)....this will be carried for 10 iteration and in every iteration 2 8 9 10 will be the error positions

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