Convert cell-array to array-of-cells, for array-of-struct creation?
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Hi, how can I convert a cell-array to an array-of-cells?
I have (following a file textscan) a cell array of format:
Fr = [{uint8([1;2;3])}, {uint32([4;5;6])}, {[7;8;9]}]
And need to get to this array of cells:
To = [{Fr{1,1}(1), Fr{1,2}(1), Fr{1,3}(1)} ;...
{Fr{1,1}(2), Fr{1,2}(2), Fr{1,3}(2)} ;...
{Fr{1,1}(3), Fr{1,2}(3), Fr{1,3}(3)}]
..without having to loop (Fr can be large) through Fr.
The reason is that I want an array-of-struct, rather than struct-of-array. Reference:
Incorrect = cell2struct(Fr,{'f1','f2','f3'},2)
Correct = cell2struct(To,{'f1','f2','f3'},2)
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Accepted Answer
Andrei Bobrov
on 18 Jun 2014
Fr = [{uint8([1;2;3])}, {uint32([4;5;6])},...
{[7;8;9]}, {uint8([11,12;13,14;15,16])}];
To = cellfun(@(x)num2cell(x,2),Fr,'un',0);
out = [To{:}];
6 Comments
Azzi Abdelmalek
on 18 Jun 2014
Sorry Andrei, I didn't read completly the explanation given by Bjoern. There is no doubt about your result, I misunderstood the new question.
More Answers (2)
Azzi Abdelmalek
on 17 Jun 2014
Edited: Azzi Abdelmalek
on 17 Jun 2014
To=num2cell([Fr{:}])
4 Comments
Azzi Abdelmalek
on 18 Jun 2014
Fr = [{uint8([1;2;3])}, {uint32([4;5;6])},...
{[7;8;9]}, {uint8([11,12;13,14;15,16])}]
mm=cellfun(@(x) size(x,2),Fr)
nn=1:numel(mm)
r=size(Fr{1},1)
dd=cell2mat(arrayfun(@(x,y) [1:x;y*ones(1,x)],mm,nn,'un',0))
[i1,j1]=meshgrid(dd(1,:),1:r)
[i2,j2]=meshgrid(dd(2,:),1:r)
out=arrayfun(@(x,y,z) Fr{x}(y,z),i2,j1,i1,'un',0)
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