Probably simple - ode45 and lsqcurvefit

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This is probably really trivial, but what I need is a function that takes a vector of parameters and a vector of time and, with ode45, outputs the p values of the ode: dp/dt=b*p-d*p^2.
What I have is:
function dpdt=diffeqn(t,p,par)
b=par(1);
d=par(2);
dpdt=b*p-d*p^2
end
and then a separate script:
[year pdata]=ode45(@diffeqn,[year],p0,[],[0.015,0.001]);
disp(pdata)
This does work fine for what is needed, but I think I need this all in one function, in order to call it in a lsqcurvefit command.

Accepted Answer

Star Strider
Star Strider on 26 May 2014
Not trivial, but not obvious either. I did this a while back in my answer to Monod kinetics and curve fitting.
Your equations are fine. To use lsqcurvefit, you just need to wrap them inside the objective function you send to it.
You can even include the initial conditions in the parameters to be estimated if necessary. That’s something we can discuss later if you need to do it.
  3 Comments
Rhys
Rhys on 26 May 2014
Edited: Rhys on 26 May 2014
Thanks, it's good to know I'm on the right track. I don't know how to wrap them into the objective function though. The closest I've come to getting the lsqcurvefit to work is using a new function:
function pdata=curvefit(par,year)
[year pdata]=ode45(@diffeqn,[year],p0,[],[par]);
end
and the command:
lsqcurvefit(@curvefit,[0.015,0.001],[year],pop) % pop is the set of data I'm trying to fit to
I thought that would work but I get the error: "Error using lsqcurvefit (line 247) Function value and YDATA sizes are incommensurate."
EDIT: I tried using the year and pop vectors as column vectors instead, and I got an answer which seems to be good. Thank you for the help! :D

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