Changing elements in an array
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I have an array of L zeros. I'm working on a program that changes the state of the elements (ones to zeros and zeros to ones). The first time through I change every element. The second time through every second element. The third time through every third element and so on to the Lth time.
I'm thinking some type of loop, similar to a Josephus problem. Somehow counting to every nth element, comparing it, and changing it. But I'm not sure of how to change to looking at the next nths (the previous n plus 1) to Lth element each loop.
Answers (1)
Image Analyst
on 19 Apr 2014
Do you mean like this:
clc;
vec = randi(2, 1, 30) - 1; % Random array of 1's and zeros.
L = sum(vec==0)
for k = 1 : L-1
selector = 1 : k : length(vec)
vec(selector) = ~vec(selector)
end
2 Comments
Image Analyst
on 19 Apr 2014
So change it to start with zero. No big deal. I assumed that you would already have vec so I just made up something. Don't use mine - use yours.
For the n'th element if you want to start it at element #n, then do so.
selector = n : n : length(vec); % Basic MATLAB concept....
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