Getting Error: Unexpected MATLAB expression.
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Question: Use Newton's method to nd three roots of x^3 - 5x + 1 = 0 accurate to within 10^-14.
My Matlab Code:
format long
x=0.5
for I = 1:10
x=x-((x.^3)-5.x+1)/(3.(x.^2)-5),
end
x=x-((x.^3)-5.x+1)/(3.(x.^2)-5),
|
Error: Unexpected MATLAB expression.
Problem: I am getting the aforementioned error and therefore, cannot find roots of the given equation in the question. Please can you find the problem and help me out? I am new to Matlab and I am learning this software. Thanks a lot! Appreciate it. :)
MATLAB Version: MATLAB R2013a
0 Comments
Accepted Answer
Star Strider
on 18 Apr 2014
Edited: Star Strider
on 18 Apr 2014
Change it to:
x=x-((x.^3)-5.*x+1)./(3.*(x.^2)-5);
It’s missing two multiplication asterisks and a dot before the division sign.
4 Comments
More Answers (1)
M SEETHA
on 14 Sep 2022
IE11=(P*Ie)*((alpha*P^(-neta))*(M^2/2)+(beta*P^(-neta))*(Pr+(xi-1)*alpha*P^(-neta)/B)*(M^2/2)-(t^2/2B^2)*(B^2*e^(-B*tp)+(1-e^(-B*M))));
THIS SHOWS UNEXPECTED MATLAB EXPRESSION KINDLY HELP ME
1 Comment
Walter Roberson
on 14 Sep 2022
(t^2/2B^2) is missing an operation between the 2 and the B
I would suggest to you that the e^ parts are confusing. People are going to wonder why you named a variable e that is not the base of natural logarithms and raise it to a power. We know that it is not the base of the natural logarithms because if it were you would have coded exp() instead. Use a different variable name for whatever your e is, such as "emissivity" so readers do not get confused thinking it is an exp() operation when it is not.
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