Convert layers of 3D matrix to list of cells
1 view (last 30 days)
Show older comments
I'd like to take a 3D matrix and convert it to a list (1D) of cells.
Example:
x(:, :, 1) = magic(3);
x(:, :, 2) = 2*magic(3);
I want c{1} to be x(:, :, 1)
I want c{2} to be x(:, :, 2)
My end goal is to create a block diagonal 2D matrix of the layers of x such that,
z = [x(:,:,1), 0
0, x(:,:,2)]
or for complete...
z = [8, 1, 6, 0, 0, 0;
3, 5, 7, 0, 0, 0;
4, 9, 2, 0, 0, 0;
0, 0, 0, 16, 2, 12;
0, 0, 0, 6, 10, 14;
0, 0, 0, 8, 18, 4]
I know I can do this very easily in a loop, but there has to be a better solution. I like the following solution but it assumes that every matrix along the diagonal is the same:
blk = magic(3);
Arguments = repmat( {blk}, 1, 100 );
A = blkdiag( Arguments{:} );
Thanks in advance
0 Comments
Answers (1)
Azzi Abdelmalek
on 14 Apr 2014
Edited: Azzi Abdelmalek
on 14 Apr 2014
Edit
x(:, :, 1) = magic(3);
x(:, :, 2) = 2*magic(3);
x(:, :, 3) = 3*magic(3);
x=arrayfun(@(ii) x(:,:,ii),1:size(x,3),'un',0)
A = blkdiag( x{:} )
3 Comments
See Also
Categories
Find more on Operating on Diagonal Matrices in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!