Scatter X and Y must be of same length

I have a 100x3 array named data that I wanted a scatter plot of

I did Scatter(data,zeros(length(data),3),'bs','filled')

Here X and Y are of same length,but the error states otherwise.

Help please?

Answer 1

[Star Strider]

Does this do what you want?

data = rand(100,3);

figure(1)
scatter3(data(:,1), data(:,2), data(:,3), 'bs', 'filled')

Replace my data statement with yours so you don’t overwrite it. I created it to test the code.

[Sid]

Oops,I should have checked for 3d scatter plot command.

[Star Strider]

Not a problem! I’m still discovering new capabilities in MATLAB.

Answer 2

[Image Analyst]

X is data - a 100 by 3 array. And you're scattering it against an array of all zeros. Why? If it even does scatter 2D array (which I doubt), all your y values will be zero. And the documentation says that X must be a vector, in other words, a 1D array, not a 2D 100 row by 3 column matrix. Maybe you want

scatter(data(:,1), data(:,2));

I have no idea. By the way, MATLAB is case sensitive so you should use scatter() not Scatter().

Answer 3

[the cyclist]

For the scatter command, the inputs have to be vectors, not arrays.

scatter(data(:,1),data(:,2))

would plot the first column against the second column.

Answer 4

[Lusiana Efrizoni]

can you help me, why this graphic like this?

I used Matlab program below

data=xlsread('MHSR.xlsx');

x1=data(:,2);

x2=data(:,3);

x3=data(:,4);

x4=data(:,5)

y = data(:,6);

X = data(:,1:4);

b = regress(y,X);

%persamaan=X\y;

[br k]=size(X);

for i=1:br

predik(i)=0.1109+(0.1203*X(i,2))-(0.8380*X(i,3))-(1*X(i,4));

end

predik=predik';

jum_mse=0;

for i=1:br

jum_mse=jum_mse+((y(i)-predik(i))^2);

end

rata_mse=jum_mse/br;

model = fitlm(X,y)

y2 = predict(model,X);

hold on

figure(1)

scatter(data(:,2), data(:,2), data(:,4),data(:,5),'filled')

%scatter(X,y2,21,'filled')

line(X,y2)

%plot(y);

%plot(y2);

xlabel('Data Ke-'),ylabel('INDEKS PRESTASI KUMULATIF')

title('Data IPK');

grid on

legend('target','line fitting')

hold off

[Image Analyst]

This is not an Answer for Sid. Please start a completely new question.