INDEX EXCEEDS MATRIX DIMENSION??
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%while running this function,i got an error message like this... %%%%doing KWFLICM
function [G1,U1]=calculateG(U1,D1,I1,m1,c,C)
[m,n]=size(I1);
G1=cell(m,n);
for i=1:m
for j=1:n
G1{i,j}=zeros(c,1);
end
end
for i=1:m
for j=1:n
for k=1:c
temp=0;
for x=i-1:i+1
for y=j-1:j+1
q=1;
if x>0&&x<m&&y>0&&y<n&&(x~=i||y~=j)
d=sqrt((i-x)^2+(j-y)^2);
% temp=temp+1/(1+d)*(1-U1{x,y}(k,1))^m1*(I1(x,y)-V2(k))^2;
% temp=temp+C{i,j}(1,q)*(1-U1{x,y}(k,1))^m1*(I1(x,y)-V2(k))^2;
temp=temp+1/(1+d)*C{i,j}(1,q)*(1-U1{x,y}(k,1))^m1*(1-D1{x,y}(k,1));
q=q+1;
end end end
G1{i,j}(k,1)=temp;
G(k)=temp;
end
for k=1:c
temp=0;
for z=1:c
% temp=temp+(G(k)/G(z))^(1/(m1-1));
a=1-D1{i,j}(z,1)+G(z);
if a~=0
temp=temp+((1-D1{i,j}(k,1)+G(k))/a)^(1/(m1-1));
else
temp=temp+((1-D1{i,j}(k,1)+G(k))/0.01)^(1/(m1-1));
end end
if temp~=0
U1{i,j}(k,1)=1/temp;
else
U1{i,j}(k,1)=1;
end
end
end
end
2 Comments
Kristopher
on 14 Feb 2014
Edited: Kristopher
on 14 Feb 2014
which line of code returns the error? Your code is pretty hard to read, but I would guess one of the loops that loops to index+1 is going past the bounds(end) or your matrix for that dimension.
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